Homework #3 A simple expert system in Prolog

 Homework #3
Grading: Each homework will be graded on the scale 100. Unless otherwise noted, the questions/parts will be weighed equal.
Part 1. [50pt] In this part of the homework, you are asked to write a simple expert system in Prolog for scheduling of classes. In your expert system, you will have rooms, courses and people. • A room has an ID, capacity (how many people it can hold), and operations hours given in one-hour increments from 8am till 5pm. Occupancy information for a room includes the hour and the name of the course taking that hour. A room can also have special equipment such as a projector, a smart board and access for the handicapped. • A course has an ID, an instructor, capacity, and one or more hours and the room information if they are assigned to a room. A course can have several students enrolled in it. A course can also have special needs such as a projector or a smart board. Of course, if there is a special needs student enrolled, it should be assigned to a room with proper access for the special needs. • An instructor has an ID and several courses taught. The instructor may have preferences for rooms with a projector or smartboard. • A student has an ID, and list of courses she/he attends. A student can also be handicapped.
Your expert system should be able to add a new student, course or a room to the system. It should respond to queries such as: • Check whether there is any scheduling conflict. • Check which room can be assigned to a given class. • Check which room can be assigned to which classes. • Check whether a student can be enrolled to a given class. • Check which classes a student can be assigned.
Part 2. In the graph below you see the possible flights between some of the cities in Turkey. Write the predicate “route(X,Y,C) – a route between X and Y exists with cost C” that checks if there is a route between any given two cities.

Your Prolog program should have all the facts and predicates/rules. See the following: % knowledge base … flight(istanbul,izmir,3). % fact: Istanbul and Izmir has a flight with cost 3. … % rules … route(X,Y,C) :- flight(X,Y,C). % a predicate indicating there exist a route between % X and Y if there is flight between X and Y with cost % C. …
A single query to complete your program should check if there is a direct route between two given cities. Alternatively, it can list all the connected cities for a given city. See the following: ?- route(edirne,X,C). X = erzurum, C = 15 ; X = antalya, C = 7 ; …